Optimal. Leaf size=297 \[ \frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {Li}_3\left (-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {9 i \text {Li}_3\left (i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {\tan ^{-1}\left (\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1)}{a x}\right )}{2 a^5}-\frac {9 \text {sech}^{-1}(a x)^2 \tan ^{-1}\left (e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {x \sqrt {\frac {1-a x}{a x+1}} (a x+1)}{20 a^4}-\frac {9 x \sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2}{40 a^4}-\frac {9 x \text {sech}^{-1}(a x)}{20 a^4}-\frac {3 x^3 \sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2}{20 a^2}-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3 \]
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Rubi [A] time = 0.20, antiderivative size = 297, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 9, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.900, Rules used = {6285, 5418, 4186, 3768, 3770, 4180, 2531, 2282, 6589} \[ \frac {9 i \text {sech}^{-1}(a x) \text {PolyLog}\left (2,-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {sech}^{-1}(a x) \text {PolyLog}\left (2,i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {PolyLog}\left (3,-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {9 i \text {PolyLog}\left (3,i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {3 x^3 \sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2}{20 a^2}-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}+\frac {x \sqrt {\frac {1-a x}{a x+1}} (a x+1)}{20 a^4}+\frac {\tan ^{-1}\left (\frac {\sqrt {\frac {1-a x}{a x+1}} (a x+1)}{a x}\right )}{2 a^5}-\frac {9 x \sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2}{40 a^4}-\frac {9 x \text {sech}^{-1}(a x)}{20 a^4}-\frac {9 \text {sech}^{-1}(a x)^2 \tan ^{-1}\left (e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3 \]
Antiderivative was successfully verified.
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Rule 2282
Rule 2531
Rule 3768
Rule 3770
Rule 4180
Rule 4186
Rule 5418
Rule 6285
Rule 6589
Rubi steps
\begin {align*} \int x^4 \text {sech}^{-1}(a x)^3 \, dx &=-\frac {\operatorname {Subst}\left (\int x^3 \text {sech}^5(x) \tanh (x) \, dx,x,\text {sech}^{-1}(a x)\right )}{a^5}\\ &=\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3-\frac {3 \operatorname {Subst}\left (\int x^2 \text {sech}^5(x) \, dx,x,\text {sech}^{-1}(a x)\right )}{5 a^5}\\ &=-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}-\frac {3 x^3 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{20 a^2}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3+\frac {\operatorname {Subst}\left (\int \text {sech}^3(x) \, dx,x,\text {sech}^{-1}(a x)\right )}{10 a^5}-\frac {9 \operatorname {Subst}\left (\int x^2 \text {sech}^3(x) \, dx,x,\text {sech}^{-1}(a x)\right )}{20 a^5}\\ &=\frac {x \sqrt {\frac {1-a x}{1+a x}} (1+a x)}{20 a^4}-\frac {9 x \text {sech}^{-1}(a x)}{20 a^4}-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}-\frac {9 x \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{40 a^4}-\frac {3 x^3 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{20 a^2}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3+\frac {\operatorname {Subst}\left (\int \text {sech}(x) \, dx,x,\text {sech}^{-1}(a x)\right )}{20 a^5}-\frac {9 \operatorname {Subst}\left (\int x^2 \text {sech}(x) \, dx,x,\text {sech}^{-1}(a x)\right )}{40 a^5}+\frac {9 \operatorname {Subst}\left (\int \text {sech}(x) \, dx,x,\text {sech}^{-1}(a x)\right )}{20 a^5}\\ &=\frac {x \sqrt {\frac {1-a x}{1+a x}} (1+a x)}{20 a^4}-\frac {9 x \text {sech}^{-1}(a x)}{20 a^4}-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}-\frac {9 x \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{40 a^4}-\frac {3 x^3 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{20 a^2}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3-\frac {9 \text {sech}^{-1}(a x)^2 \tan ^{-1}\left (e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {\tan ^{-1}\left (\frac {\sqrt {\frac {1-a x}{1+a x}} (1+a x)}{a x}\right )}{2 a^5}+\frac {(9 i) \operatorname {Subst}\left (\int x \log \left (1-i e^x\right ) \, dx,x,\text {sech}^{-1}(a x)\right )}{20 a^5}-\frac {(9 i) \operatorname {Subst}\left (\int x \log \left (1+i e^x\right ) \, dx,x,\text {sech}^{-1}(a x)\right )}{20 a^5}\\ &=\frac {x \sqrt {\frac {1-a x}{1+a x}} (1+a x)}{20 a^4}-\frac {9 x \text {sech}^{-1}(a x)}{20 a^4}-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}-\frac {9 x \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{40 a^4}-\frac {3 x^3 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{20 a^2}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3-\frac {9 \text {sech}^{-1}(a x)^2 \tan ^{-1}\left (e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {\tan ^{-1}\left (\frac {\sqrt {\frac {1-a x}{1+a x}} (1+a x)}{a x}\right )}{2 a^5}+\frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {(9 i) \operatorname {Subst}\left (\int \text {Li}_2\left (-i e^x\right ) \, dx,x,\text {sech}^{-1}(a x)\right )}{20 a^5}+\frac {(9 i) \operatorname {Subst}\left (\int \text {Li}_2\left (i e^x\right ) \, dx,x,\text {sech}^{-1}(a x)\right )}{20 a^5}\\ &=\frac {x \sqrt {\frac {1-a x}{1+a x}} (1+a x)}{20 a^4}-\frac {9 x \text {sech}^{-1}(a x)}{20 a^4}-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}-\frac {9 x \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{40 a^4}-\frac {3 x^3 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{20 a^2}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3-\frac {9 \text {sech}^{-1}(a x)^2 \tan ^{-1}\left (e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {\tan ^{-1}\left (\frac {\sqrt {\frac {1-a x}{1+a x}} (1+a x)}{a x}\right )}{2 a^5}+\frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {(9 i) \operatorname {Subst}\left (\int \frac {\text {Li}_2(-i x)}{x} \, dx,x,e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {(9 i) \operatorname {Subst}\left (\int \frac {\text {Li}_2(i x)}{x} \, dx,x,e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}\\ &=\frac {x \sqrt {\frac {1-a x}{1+a x}} (1+a x)}{20 a^4}-\frac {9 x \text {sech}^{-1}(a x)}{20 a^4}-\frac {x^3 \text {sech}^{-1}(a x)}{10 a^2}-\frac {9 x \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{40 a^4}-\frac {3 x^3 \sqrt {\frac {1-a x}{1+a x}} (1+a x) \text {sech}^{-1}(a x)^2}{20 a^2}+\frac {1}{5} x^5 \text {sech}^{-1}(a x)^3-\frac {9 \text {sech}^{-1}(a x)^2 \tan ^{-1}\left (e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {\tan ^{-1}\left (\frac {\sqrt {\frac {1-a x}{1+a x}} (1+a x)}{a x}\right )}{2 a^5}+\frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {sech}^{-1}(a x) \text {Li}_2\left (i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}-\frac {9 i \text {Li}_3\left (-i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}+\frac {9 i \text {Li}_3\left (i e^{\text {sech}^{-1}(a x)}\right )}{20 a^5}\\ \end {align*}
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Mathematica [A] time = 0.64, size = 281, normalized size = 0.95 \[ \frac {8 a^5 x^5 \text {sech}^{-1}(a x)^3-6 a^3 x^3 \sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2-4 a^3 x^3 \text {sech}^{-1}(a x)+18 i \text {sech}^{-1}(a x) \text {Li}_2\left (-i e^{-\text {sech}^{-1}(a x)}\right )-18 i \text {sech}^{-1}(a x) \text {Li}_2\left (i e^{-\text {sech}^{-1}(a x)}\right )+18 i \text {Li}_3\left (-i e^{-\text {sech}^{-1}(a x)}\right )-18 i \text {Li}_3\left (i e^{-\text {sech}^{-1}(a x)}\right )+2 a x \sqrt {\frac {1-a x}{a x+1}} (a x+1)-9 a x \sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2-18 a x \text {sech}^{-1}(a x)+9 i \text {sech}^{-1}(a x)^2 \log \left (1-i e^{-\text {sech}^{-1}(a x)}\right )-9 i \text {sech}^{-1}(a x)^2 \log \left (1+i e^{-\text {sech}^{-1}(a x)}\right )+40 \tan ^{-1}\left (\tanh \left (\frac {1}{2} \text {sech}^{-1}(a x)\right )\right )}{40 a^5} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.64, size = 0, normalized size = 0.00 \[ {\rm integral}\left (x^{4} \operatorname {arsech}\left (a x\right )^{3}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{4} \operatorname {arsech}\left (a x\right )^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.34, size = 0, normalized size = 0.00 \[ \int x^{4} \mathrm {arcsech}\left (a x \right )^{3}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{4} \operatorname {arsech}\left (a x\right )^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int x^4\,{\mathrm {acosh}\left (\frac {1}{a\,x}\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{4} \operatorname {asech}^{3}{\left (a x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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